ABCD is cyclic quadrilateral in which ∠A = x°, ∠B = 5y°, ∠C = 2x° and ∠D = y°. What is the value of (3x - y)?

120 90 150 60

150

\(\angle\)A + \(\angle\)C = 180 = x + 2x = 180 = 3x = 180 = x = \({60}^\circ\) \(\angle\)B + \(\angle\)D = 180 5y + y = 180 = 6y = 180 = y = \({30}^\circ\) (3x - y) = (60 x 3 - 30) = 180 - 30 = 150 Therefore, (3x - y) is 150.