The area bounded by $x=1, x=2, xy=1$ and x-axis is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\log 2$
So required area
$=\int\limits_1^2\frac{1}{x}dx$
$⇒|\log x|_1^2$
$=\log 2-\log 1$
$=\log 2$
The area bounded by $x=1, x=2, xy=1$ and x-axis is :
Correct answer: option 1
The correct answer is Option (1) → $\log 2$
So required area
$=\int\limits_1^2\frac{1}{x}dx$
$⇒|\log x|_1^2$
$=\log 2-\log 1$
$=\log 2$