The present population of a village is 15280. If the number of males increases by 25% and the number of females increases by 15%, then the population will become 18428. The difference between present population of males and females in the village is:

1840

25% = \(\frac{1}{4}\)  & 15% = \(\frac{3}{20}\) 

Let number of males = x & Number of females = y

x + y = 15280   ----(1)

Number of increased male = (1 + \(\frac{1}{4}\))x = \(\frac{5x}{4}\) 

Number of increased female = ( 1 + \(\frac{3}{20}\) ) y = \(\frac{23y}{20}\) 

Increased New population = 18428

i.e  \(\frac{5x}{4}\)  + \(\frac{23y}{20}\)  =  18428

25x + 23y = 368560   ----(2)

Multiply equation 1 by 25 and subtract equation 2 from it

25y - 23y = 382000 - 368560

2y = 13440

y = 6720 & x = 15280 - 6720 = 8560

Difference b/w present male & female = 8560 - 6720 = 1840