If $ (x + \frac{1}{x}) = 7.5$, what is the value of $(x^2 +\frac{1}{x^2})$ ?

54.25 52.25 56.25 58.25

54.25

We know that, If x + \(\frac{1}{x}\)  = n then, $x^2 +\frac{1}{x^2}$ = n2 - 2 If $ (x + \frac{1}{x}) = 7.5$, then, the value of $(x^2 +\frac{1}{x^2})$ = (7.5)2 - 2 = 56.25 - 2 = 54.25