If $ (x + \frac{1}{x}) = 7.5$, what is the value of $(x^2 +\frac{1}{x^2})$ ?
Answer & explanation
Correct answer: option 1
We know that,
If x + \(\frac{1}{x}\) = n
then, $x^2 +\frac{1}{x^2}$ = n2 - 2
If $ (x + \frac{1}{x}) = 7.5$,
then, the value of $(x^2 +\frac{1}{x^2})$ = (7.5)2 - 2 = 56.25 - 2 = 54.25