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CUET
Physics
Alternating Current
Calculate the capacitance in a circuit with current 2 A and peak voltage of 220 V changing its direction 50 times a second.
0.85 F
0.35 F
1.22 F
30 μF
Xc = V/I = 220 V/2 A = 110 V/A
also, Xc = 1/wC ⇒ C = 1/Xcw
C = = 1/2π x 50 x 110 = 30 μF