Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

Calculate the capacitance in a circuit with current 2 A and peak voltage of 220 V changing its direction 50 times a second.

Options:

0.85 F

0.35 F

1.22 F

30 μF

Correct Answer:

30 μF

Explanation:

Xc = V/I = 220 V/2 A = 110 V/A

also, Xc = 1/wC ⇒ C = 1/Xc

C = = 1/2π x 50 x 110 = 30 μF