The sides AB and AC of a ΔABC are extended to P and Q respectively.  If the bisectors of ∠PBC and ∠QCB intersect at O and ∠A = 82°, then ∠BOC is equal to?

41° 49° 98° 100°

49°

∠BOC = 90° - \(\frac{1}{2}\) ∠A          = 90° - 41° = 49°