Practicing Success
Practicing Success
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If 4cot A = 5, then what is the value of 6sec A tan A ? |
$\frac{20\sqrt{41}}{21}$ $\frac{25\sqrt{41}}{24}$ $\frac{24\sqrt{41}}{25}$ $\frac{3}{2}\sqrt{41}$ |
$\frac{24\sqrt{41}}{25}$ |
4cot A = 5 cotA = \(\frac{5}{4}\) P2 + B2 = H2 42 + 52 = H2 H = √41 6sec A tan A = 6 × \(\frac{ √41 }{5}\) × \(\frac{4}{5}\) = \(\frac{24 . √41}{25}\) |
