Practicing Success
Practicing Success
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Simplify \(\frac{2sin (\frac{\pi}{4} + θ) sin (\frac{\pi}{4} - θ)}{cos 2θ}\) |
sin( \(\frac{π}{2}\) - 2θ) 0 cos ( \(\frac{π}{4}\) + θ) 1 |
1 |
\(\frac{2sin(\frac{π}{4} + θ) sin (\frac{π}{4} - θ)}{cos 2θ}\) ⇒ \(\frac{cos 2 - cos (\frac{π}{2})}{cos 2 θ}\) ( because 2sinAsinB = cos (A-B) - cos ( A+B)) ⇒ \(\frac{cos2 θ - 0}{cos 2 θ}\) = 1 |
