A ray is incident normally on the face of an equilateral prism of refracting angle of 60°. The refractive index of the prism is $\frac{2}{\sqrt{3}}$. The angle of deviation will be: |
60° 30° 45° 90° |
30° |
The correct answer is Option (3) → 30° Using Snell's law, $μ\sin r = \sin e$ and, for an equilateral triangle, $r_1+r_2=A$ $[r_1=0°]$ $⇒r_2=60°$ $∴\frac{2}{\sqrt{3}}\sin 60°=\sin e$ $\frac{2}{\sqrt{3}}×\frac{\sqrt{3}}{2}=\sin e⇒e=90°$ and, Angle of deviation $(δ)=(i+e)-A$ $=(0+90)-60=30°$ |