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The potential difference between two points in a wire 8.0 m apart is 8.0 V when the current density is 4.0 x 107 Am–2. The resistivity of the material is
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$ 2.5 \times 10^{-6}\Omega -m$ $ 2.5 \times 10^{-7}\Omega -m$ $ 2.5 \times 10^{-8}\Omega -m$ $ 2.5 \times 10^{-9}\Omega -m$ |
$ 2.5 \times 10^{-8}\Omega -m$ |
$ E = \frac{V}{d} = 1 V/m$ $ \rho = \frac{E}{J} = \frac{1}{4\times 10^7} = 2.5\times 10^{-8} \Omega -m$ |
