The area of the region {$(x, y): x^2 +y^2≤1≤x+y$ } is :
Answer & explanation
Correct answer: option 1
The correct answer is option (1) → $\left(\frac{\pi}{4}-\frac{1}{2}\right)$
required area = area of quarter circle - area of triangle
$=\frac{\pi}{4}-\frac{1}{2}$