Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Time, Speed and Distance

Question:

150 m long train crossed a person standing on platform in 9 seconds. The speed of train in km/hr is

Options:

\(\frac{50}{3}\)

60

\(\frac{50}{9}\)

\(\frac{250}{54}\)

Correct Answer:

60

Explanation:

When a train cross a man then the distance traveled by train is equals to length of train.

Now,

Speed = \(\frac{Distance}{Time}\)

Distance = length of train = 150m

Time = 9 sec

Speed of train = \(\frac{150}{9}\) m/sec

                       = \(\frac{50}{3}\) m/sec

                       = \(\frac{50}{3}\) × \(\frac{18}{5}\) km/hr

                       = 60 km/hr