If the given figure, ∠ACB +&nbs

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Home Questions 9S6CQ7CYNA

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Geometry

Question:

If the given figure, ∠ACB + ∠BAC = 80°;∠BDE = 35°; ∠BCE = 45°, then the marked angle ∠CED is :

Options:

150°

120°

160°

135°

Correct Answer:

160°

Explanation:

We have,

∠ACB + ∠BAC = 80^o

∠BDE = 35^o

∠BCE = 45^o

Now, we know that,

∠DBC = ∠ACB + ∠BAC

∠DBC = 80^o

∠DBC + ∠BCE = ∠CPD

∠CPD = 80^o + 45^o = 125^o

∠CED = ∠CPD + ∠BDE

∠CED = 125^o + 35^o = 160^o