8 coins are tossed simultaneously. The probability of getting at least 6 heads is
Answer & explanation
Correct answer: option 4
The required probability $= {^8C}_6 \left(\frac{1}{2}\right)^6.\left(\frac{1}{2}\right)^2 + {^8C}_7 \left(\frac{1}{2}\right)^7.\left(\frac{1}{2}\right) + {^8C}_8 \left(\frac{1}{2}\right)^8 = \frac{37}{256}.$