If x + \(\frac{1}{16x}\) = 3, then 16x3 + \(\frac{1}{256x^3}\) is equals to:
Answer & explanation
Correct answer: option 3
Given, x + \(\frac{1}{16x}\) = 3
multiply by 4
so, 4x + \(\frac{1}{4x}\) = 12
64x3 + \(\frac{1}{64x^3}\) = 1728 - (3 × 12) = 1692
Divide by 4
16x3 + \(\frac{1}{256x^3}\) = \(\frac{1692}{4}\) = 423