The value of $\left(\frac{1-\cot \theta}{1-\tan \theta}\right)^2-1$ when $0^{\circ}< \theta<90^{\circ}$, is equal to:
Answer & explanation
Correct answer: option 3
( \(\frac{1 - cotθ }{1 - tanθ}\) )2 - 1
= ( \(\frac{sinθ - cosθ }{sinθ}\) )2 × ( \(\frac{ cosθ }{cosθ - sinθ}\) )2 - 1
= ( \(\frac{cosθ }{sinθ}\) )2 - 1
= $\cot ^2 \theta-1$