$f (x) =1+[cos x]x$, in $0<x≤\frac{π}{2}$
Answer & explanation
Correct answer: option 1
Since f(x) = 1 in $0<x≤\frac{π}{2}$ [∵ [cos x] = 0]
f(x) is continuous in $[0,\frac{π}{2}]$
$f (x) =1+[cos x]x$, in $0<x≤\frac{π}{2}$
Correct answer: option 1
Since f(x) = 1 in $0<x≤\frac{π}{2}$ [∵ [cos x] = 0]
f(x) is continuous in $[0,\frac{π}{2}]$