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Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) (A)-(II), (B)-(I), (C)-(III), (D)-(IV) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) |
(A)-(II), (B)-(I), (C)-(III), (D)-(IV) |
The correct answer is Option (3) → (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
Given formulas and physical quantities: (A) $I = ne A v_d$ - $n$ = number density of charge carriers - $e$ = charge of electron - $A$ = cross-sectional area - $v_d$ = drift velocity This formula gives the current in a conductor. → (II) Current (B) $v_d / E$ - $v_d$ = drift velocity - $E$ = applied electric field Mobility $\mu$ is defined as the ratio of drift velocity to electric field: $\mu = v_d / E$. → (I) Mobility (C) $ne^2 \tau / m$ - $n$ = charge carrier density - $e$ = charge - $\tau$ = relaxation time - $m$ = mass of electron Electrical conductivity $\sigma = ne^2 \tau / m$. → (III) Conductivity (D) $m / ne^2 \tau$ - This is the reciprocal of conductivity, hence represents resistivity $\rho$. → (IV) Resistivity |
