If a young man drives his vehicle 25 km/hr he has to spend Rs. 2 per km on petrol. If he drives it at faster speed of 40 km/hr, the petrol cost increases to Rs. 5 per km. He has Rs. 100 to spend on petrol and travel within one hour. The maximum distance he travels is :

30 km

The correct answer is Option (3) → 30 km

Objective fn = x+ y if he travels

$2x+5y≤100$

$\frac{x}{25}+\frac{y}{40}≤1,x,y≥0$

x kms at 25

y kms at 40

checking at corner points

$Z_A=20$

$Z_C=30$ → Maximum distance

$Z_E=25$