The potential at a point in an electric field is 3 X 103 V. The work done in moving a charge of 10 μC from infinity to that point is-
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 3 X 10−2 J
The electric potential at a point is the work done by an external agent in bringing a unit positive charge from infinity to that point. For a charge q the work is q times the potential.
\( \displaystyle W = qV \)
\( \displaystyle q = 10\,\mu\mathrm{C} = 10\times10^{-6}\,\mathrm{C} = 1\times10^{-5}\,\mathrm{C} \)
\( \displaystyle W = (1\times10^{-5}\,\mathrm{C}) \times (3\times10^{3}\,\mathrm{V}) \)
\( \displaystyle W = 3\times10^{-2}\,\mathrm{J} \)