Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Continuity and Differentiability

Question:

$x=a \cos ^3 t, y=a \sin ^3 t$, then $\frac{d y}{d x}$ is

Options:

– tan t

–cos t

–cosec t

–cot t

Correct Answer:

– tan t

Explanation:

$\frac{d y}{d t}=3 a \sin ^2 t \cos t, \frac{d x}{d t}=-3a \cos ^2 t \sin t$

$\frac{d y}{d x}=\frac{3 a \sin ^2 t \cos t}{-3 a \cos ^2 t \sin t}=-\tan t$

Hence (1) is correct answer.