Practicing Success
$x=a \cos ^3 t, y=a \sin ^3 t$, then $\frac{d y}{d x}$ is |
– tan t –cos t –cosec t –cot t |
– tan t |
$\frac{d y}{d t}=3 a \sin ^2 t \cos t, \frac{d x}{d t}=-3a \cos ^2 t \sin t$ $\frac{d y}{d x}=\frac{3 a \sin ^2 t \cos t}{-3 a \cos ^2 t \sin t}=-\tan t$ Hence (1) is correct answer. |