If tan θ = 15, then what is the value of cosθ ?

$\sqrt{226}$ $\frac{1}{\sqrt{224}}$ $\frac{1}{\sqrt{226}}$ $\sqrt{224}$

$\frac{1}{\sqrt{226}}$

tan θ = 15 { we know, tan θ = \(\frac{P}{B}\) } By using pythagoras theorem, P² + B² = H² 15² + 1² = H² H = \(\sqrt { 226}\) Now, cosθ = \(\frac{B}{H}\)  = \(\frac{1}{√226}\)