Practicing Success
For a discharging capacitor in a series RC circuit, its potential energy is one- half of its initial value at time t. This time t in terms of time constant $\tau$ is |
$\frac{2\tau}{ln2}$ $\tau ln2$ $2\tau ln2$ $\frac{\tau}{2} ln2$ |
$\frac{\tau}{2} ln2$ |
For Potential energy to become half the charge in capacitor becomes $\frac{1}{\sqrt 2}$ times. $ q = q_0 e^{-\frac{t}{RC}} = \frac{q_0}{\sqrt 2}$ $ \frac{1}{\sqrt 2} = e^{-\frac{t}{RC}}$ $ \frac{t}{RC} = \frac{1}{2}ln2$ $ t = \frac{\tau}{2} ln2$ |