Practicing Success
If θ is an acute angle and 5 sinθ + 12 cosθ = 13, find the value of \(\frac{sinθ}{tanθ}\) + cosθ. |
\(\frac{168}{13}\) \(\frac{24}{13}\) \(\frac{24}{\sqrt {13}}\) \(\frac{168}{\sqrt {13}}\) |
\(\frac{24}{13}\) |
In equation → 5 sinθ + 12 cosθ = 13 If the coefficients of sinθ and cosθ and constant are making a triplet then → 5 sinθ + 12 cosθ = 13 ↓ ↓ ↓ P B H Therefore, \(\frac{sinθ}{tanθ}\) + cosθ = \(\frac{sinθ}{\frac{sinθ}{cosθ}}\) + cosθ = cosθ + cosθ = 2 cosθ = 2 × \(\frac{12}{13}\) = \(\frac{24}{13}\) |