Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:
What is the derivative of $y=\sqrt{e^{\sqrt x}}$?
Options:
$\frac{e^{\sqrt x/2}}{4\sqrt x}$
$\frac{e^{\sqrt x/2}}{2\sqrt x}$
$\frac{e^{\sqrt x}}{4\sqrt x}$
$\frac{e^{\sqrt x/2}}{4x}$
Correct Answer:
$\frac{e^{\sqrt x/2}}{4\sqrt x}$
Explanation:
We can write $y=(e^{\sqrt x})^{1/2}$. Then differentiating both sides w.r.to x we get $\frac{dy}{dx}$.