Practicing Success
If a and b are the lengths of two sides of a triangle such that the product ab = 24, where a and are integers, then how many such triangles are possible? |
18 16 12 15 |
15 |
Let us consider that 3rd side of triangle is = x abx is a triangle iff ( a - b ) < x < ( a + b ) It is given that :- ab = 24 So, Possible values of a and b are :- ( 1 , 24 ) ( 24 - 1 ) < x < ( 24 + 1 ) = 23 < x < 25 so, x = 24 ( 2 , 12 ) ( 12 - 2 ) < x < (12 + 2 ) = 10 < x < 14 so, x = 11, 12, 13 ( 3, 8 ) ( 8 - 3) < x < ( 8 + 3) = 5 < x < 11 so, x = 6 , 7, 8, 9, 10 ( 4 , 6 ) ( 6 - 4) < x < ( 6 + 4) = 2 < x < 10 so, x = 3 , 4, 5, 6, 7, 8, 9 So, Total number of values of x = 16 So, Possible number of triangles is = 16
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