AB is the diameter of a circle. A point C is situated on the tangent drawn on point A. If AB = 24 cm, and AC = 7 cm then find the length of BC:

50 cm 15 cm 25 cm 26 cm

25 cm

We know that, (Hypotnuese)2 = (perpendicular)2 + (base)2 We have, AB = 24 cm  AC = 7 cm   ΔABC is right angle triangle = = (BC)2 = (AB)2 + (AC)2  = BC = \(\sqrt {24^2 + 7^2 }\)  = BC = \(\sqrt {625 }\)  = 25 cm