The radius of innermost electron orbit of a hydrogen atom is $5.3×10^{-11} m$. What is the radius of n = 2 orbit?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $2.12×10^{-10} m$
In the Bohr Model of the hydrogen atom, the radius of n-th electron orbit is -
$r_n=r_1×n^2$ [$r_1$ = Radius of inner most circle]
$∴r_2=r_1×2^2$
$=5.3×10^{-11}×4$
$=2.12×10^{-10}m$