Practicing Success
Practicing Success
CUET Preparation Today
A charge of 2 µC is brought from B to C along the path as shown by arrow in the figure. The work done is
|
0.75 J 0.6 J 0.06 J 0.075 J |
0.075 J |
W = $\frac{q_1 q_2}{4 \pi \varepsilon_0}\left[\frac{1}{r_f}-\frac{1}{r_i}\right]$ $=10 \times 2 \times 10^{-12} \times 9 \times 10^9\left[\frac{1}{0.6}-\frac{1}{0.8}\right]$ = 0.075 J |
