Practicing Success
A point P is lying at a distance r (< a) from the centre of shell of radius a. If E and V be the gravitational field and potential at the point P then, V = ? |
E = 0 E = $-\frac{GM}{r^2}$ v = 0 V = $-\frac{GM}{a}$ |
V = $-\frac{GM}{a}$ |
The field inside the shell is zero and so potential inside the shell is constant equal to the value that exists at the surface i.e. $-\frac{GM}{a}$. |