Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

A point P is lying at a distance r (< a) from the centre of shell of radius a. If E and V be the gravitational field and potential at the point P then, V = ?

Options:

E = 0

E = $-\frac{GM}{r^2}$

v = 0

V = $-\frac{GM}{a}$

Correct Answer:

V = $-\frac{GM}{a}$

Explanation:

The field inside the shell is zero and so potential inside the shell is constant equal to the value that exists at the surface i.e. $-\frac{GM}{a}$.