If $sec^2 θ=\frac{4}{3}$, then the value of $ cosec (θ + 30^o)$ is _________. [ θ is the acute angle.]
Answer & explanation
Correct answer: option 2
sec²θ = \(\frac{4}{3}\)
secθ = \(\frac{2}{√3}\)
{ we know, sec30º = \(\frac{2}{√3}\) }
So, θ = 30º
Now,
cosec ( θ + 30º )
= cosec ( 60º )
= \(\frac{2}{√3}\)