Practicing Success
Practicing Success
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If $sec^2 θ=\frac{4}{3}$, then the value of $ cosec (θ + 30^o)$ is _________. [ θ is the acute angle.] |
$-\frac{2}{\sqrt{3}}$ $\frac{2}{\sqrt{3}}$ $\frac{1}{\sqrt{3}}$ $-\frac{1}{\sqrt{3}}$ |
$\frac{2}{\sqrt{3}}$ |
sec²θ = \(\frac{4}{3}\) secθ = \(\frac{2}{√3}\) { we know, sec30º = \(\frac{2}{√3}\) } So, θ = 30º Now, cosec ( θ + 30º ) = cosec ( 60º ) = \(\frac{2}{√3}\) |
