Practicing Success
Practicing Success
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The graph of y = f(x) is symmetrical about the line x = 1, then |
$f (−x) = f (x)$ $f (1 + x) = f (1 − x)$ $f (x + 1) = f (x − 1)$ none of these |
$f (1 + x) = f (1 − x)$ |
Graph of y = f(x) is symmetric about the line x = 0 if f(−x) = f(x) i.e. if f(0 − x) = f(0 + x) ∴ Graph of y = f(x) is symmetric about x = 1 if f(1 − x) = f(1 + x). |
