Practicing Success
If the function $f(x)=x^4-62 x^2+ax+9$ attains its local maximum value at $x=1$, then a is equal to : |
120 110 100 90 |
120 |
$f(x)=x^4-62 x^2+a x+9$ local maxima is at x = 1 $f'(x)=4 x^3-124 x+a$ so $f'(1)=0=4-124+a$ (at maxima / minima slope of function is null) so a = 124 - 4 so a = 120 |