CUET Preparation Today
What is the area (in sq cm) of an equilateral triangle of side 25 cm? |
\(\frac{624}{4}\)\(\sqrt{3}\) \(\frac{625}{4}\)\(\sqrt{3}\) \(\frac{729}{4}\)\(\sqrt{3}\) \(\frac{144}{4}\)\(\sqrt{3}\) |
\(\frac{625}{4}\)\(\sqrt{3}\) |
Area of equilateral triangle = \(\frac{ \sqrt{3}}{4}\)a2 = \(\frac{ \sqrt{3}}{4}\) × 25 × 25 = \(\frac{625}{4}\)\(\sqrt{3}\) cm2 |
