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For a $3×3 $ matrix $A= [a_{ij}],$ whose element $a_{ij}$ is given by $a_{ij}=\sqrt{i^(2)+3j}$ then what is element $a_{31}$ ? |
$\sqrt{6}$ $\sqrt{7}$ $2\sqrt{3}$ $2\sqrt{2}$ |
$2\sqrt{3}$ |
Given $a_{ij}=\sqrt{i^{2}+3j}$ To find $a_{31}$ Here $i=3,\; j=1$ $a_{31}=\sqrt{3^{2}+3(1)}$ $=\sqrt{9+3}$ $=\sqrt{12}$ $=2\sqrt{3}$ The element $a_{31}$ is $2\sqrt{3}$. |
