If $\vec{a}=4\hat{i}+6\hat{j}$ and $\vec{b}=3\hat{j}+4\hat{k}$, then the vector form of the component of $\vec{a}$ along $\vec{b}$ is

$\frac{18}{25}(3\hat{j}+4\hat{k})$

The correct answer is Option (2) → $\frac{18}{25}(3\hat{j}+4\hat{k})$ ##

Vector component of $\vec{a}$ along $\vec{b}$

$= \left( \frac{\vec{a} \cdot \vec{b}}{|\vec{b}|^2} \right) \vec{b} = \frac{18}{25}(3\hat{j}+4\hat{k})$