If the vertices of a $ΔABC$ are $A(1, 3), B(3, 5)$ and $C(x, y)$ and centroid is $\left(\frac{11}{3},\frac{16}{3}\right)$, then $(x, y)$ is :

(7, 8)

The vertices of a ΔABC are A(1,3),B(3,5) and C(x,y) and centroid is (11/3,16/3)

Centroid = [(x1+x2+x3)/3 , (y1+y2+y3)/3] = (11/3,16/3)

1+3+x = 11 ⇒ x = 7

and 3+5+y = 16 ⇒ y = 8

The correct answer is option (2) : (7, 8)