A generator develops an e.m.f of 150 V and has a terminal potential difference of 125 V, when the armature current is 50 A, the resistance of armature will be
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $0.5 \Omega$
$E=V+IR$ [formula]
where,
E, emf of generator = 150 V
V, terminal potential difference = 125 V
I, Armature current = 50 A
∴ R=\frac{E-V}{I}=\frac{150-125}{50}$
$=0.5\Omega$