A generator develops an e.m.f of 150 V and has a terminal potential difference of 125 V, when the armature current is 50 A, the resistance of armature will be

$0.5 \Omega$

The correct answer is Option (2) → $0.5 \Omega$

$E=V+IR$ [formula]

where,

E, emf of generator = 150 V

V, terminal potential difference = 125 V

I, Armature current = 50 A

∴ R=\frac{E-V}{I}=\frac{150-125}{50}$

$=0.5\Omega$