CUET Preparation Today
A random variable 'X' has the probability distribution
then P(X > 1) is : |
$\frac{3}{4}$ $\frac{1}{4}$ $\frac{1}{2}$ $\frac{2}{3}$ |
$\frac{1}{2}$ |
The correct answer is Option (3) → $\frac{1}{2}$ $∑P(X)=1$ $k+k+2k=1$ $4k=1$ $k=\frac{1}{4}$ $P(X>1)$ $P(X=2)$ $=2k$ $=2.\frac{1}{4}=\frac{1}{2}$ |
