If the volume of a sphere is $697\frac{4}{21} cm^3$, then its radius is : (Take $\pi=\frac{22}{7}$) |
6 cm 5 cm 4.5 cm 5.5 cm |
5.5 cm |
Given, The volume of a sphere = $697\frac{4}{21} cm^3$ = \(\frac{14641}{21}\) We also know that, The volume of a sphere = \(\frac{4}{3}\) πr3 equating both of them, \(\frac{4}{3}\) × \(\frac{22}{7}\) × r3 = \(\frac{14641}{21}\) r3 = \(\frac{14641}{21}\) × \(\frac{7}{22}\) × \(\frac{3}{4}\) on solving, r3 = 166.375 r = \(\sqrt[3]{166.375}\) r = 5.5cm |