Equation of the plane such that foot of altitude drawn from (-1, 1, 1) to the plane has the coordinate (3, -2, -1), is:
Answer & explanation
Correct answer: option 2
Clearly, the direction ratio of the plane are
4, –3, –2
Thus equation of plane will be
4x – 3y – 2z = d
It will necessarily pass through (3, –2, –1)
i.e,, d = 12 + 6 + 2 = 20
Thus the equation of plane is
4x – 3y – 2z = 20