Calculate the area of a sector of a circle with radius 10 metres and angle of 90 degrees at the centre.

78.5 cm²

Radius = 10 m,

Angle = \({90}^\circ\)

Solution

Area of the sector = \(\Pi \) \(\frac{10 × 10}{360}\) x \({90}^\circ\)

⇒ \(\frac{22}{7}\) x \(\frac{100}{4}\) = 78.57 = 78.5 \( {m }^{2 } \)

Therefore, area of sector is 78.5 \( {m }^{2 } \)