Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Continuity and Differentiability

Question:

Define a function $f:\mathbb{R}\rightarrow \mathbb{R}$ as $f(x)=\begin{cases}\frac{\sin x}{x}& \text{if}\hspace{.2cm} x \neq 0\\ 1,& \text{otherwise} \end{cases}$. Then $f$ is

Options:

$f$ is continuous everywhere

$f$ is discontinuous at $x=0$

$f$ is differentiable at $x=0$

None of the above

Correct Answer:

$f$ is continuous everywhere

Explanation:

We have $\lim_{x \to 0}\frac{sin x}{x}=1$ and $f(0)=1$. So $f$ is continuous at $x=0$. $f$ is continuous at every other point because $\sin x$ is a continuous function and $f(x)=x$ is also continuous.