The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly : |
1.24 x 10 nm 1.24 x 10-3 nm 1.24 nm 1.24 x 10-6 nm |
1.24 x 10-3 nm |
Use : E = \(\frac{h c}{\lambda}\) E = 1 MeV $ \Rightarrow \lambda = \frac{hc}{E} = \frac{1240}{10^6}nm = 1.24 \times 10^{-3} nm$
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