The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly :
Answer & explanation
Correct answer: option 2
Use : E = \(\frac{h c}{\lambda}\)
E = 1 MeV
$ \Rightarrow \lambda = \frac{hc}{E} = \frac{1240}{10^6}nm = 1.24 \times 10^{-3} nm$