Match List-I (Common name) with List-II (IUPAC name)
|
List-I Common Name |
List-II IUPAC name |
|
(A) Aniline |
(I) N-Phenylethanamide |
|
(B) Acetanilide |
(II) Benzenamine |
|
(C) Sulphanilic acid |
(III) Prop-2-en-1-amine |
|
(D) Allylamine |
(IV) p-aminobenzene sulphonic acid |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
In the IUPAC system an amine is named by replacing the final "e" of the parent hydrocarbon by "amine" (benzene becomes benzenamine); an amide is named from the acid by changing "-oic acid" to "-amide", and a group on the nitrogen is shown with the prefix N-.
(A) Aniline — This matches (II) Benzenamine. \( \ce{C6H5NH2} \) is an amino group on a benzene ring.
(B) Acetanilide — This matches (I) N-Phenylethanamide. \( \ce{CH3CONHC6H5} \) is ethanamide with a phenyl group on the nitrogen; it is made by acetylation of aniline:
\( \displaystyle \ce{C6H5NH2 + (CH3CO)2O -> C6H5NHCOCH3 + CH3COOH} \)
(C) Sulphanilic acid — This matches (IV) p-aminobenzene sulphonic acid. It is formed by sulphonation of aniline and carries \( \ce{-NH2} \) and \( \ce{-SO3H} \) para to each other (4-aminobenzenesulphonic acid).
(D) Allylamine — This matches (III) Prop-2-en-1-amine. \( \ce{CH2=CH-CH2-NH2} \) has a three-carbon chain with a double bond between C-2 and C-3 and the amino group on C-1.
Shortcut: (A)-(II) appears only in Option (1).