CUET Preparation Today
CUET
Physics
Alternating Current
a
b
c
d
Power dissipated in A.C Circuit is given by P = $V_{rms}I_{rms} cos\theta$
$V_{rms} = \frac{100}{\sqrt 2} V$
$I_{rms} = \frac{100}{\sqrt 2} mA$
cos$\frac{\pi}{3} = \frac{1}{2}$
⇒ P = 2.5 W
