Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

In an a.c. circuit, V and I are given by 
$V = 100 \sin (100 t) volt$
$I=100 \sin (100t+π/3) mА$.
The power dissipated in the circuit is

Options:

$10^4$ watt

10 watt

2.5 watt

5 watt

Correct Answer:

2.5 watt

Explanation:

Power dissipated in A.C Circuit is given by P = $V_{rms}I_{rms} cos\theta$

$V_{rms} = \frac{100}{\sqrt 2} V$

$I_{rms} = \frac{100}{\sqrt 2} mA$

cos$\frac{\pi}{3} = \frac{1}{2}$

⇒ P = 2.5 W