In an a.c. circuit, V and I are given by
$V = 100 \sin (100 t) volt$
$I=100 \sin (100t+π/3) mА$.
The power dissipated in the circuit is
Answer & explanation
Correct answer: option 3
Power dissipated in A.C Circuit is given by P = $V_{rms}I_{rms} cos\theta$
$V_{rms} = \frac{100}{\sqrt 2} V$
$I_{rms} = \frac{100}{\sqrt 2} mA$
cos$\frac{\pi}{3} = \frac{1}{2}$
⇒ P = 2.5 W