If sin A = 6/7, then what is the value of sec A ?

sinA = \(\frac{6}{7}\)

{ we know that sinθ = \(\frac{P}{H}\) }

By using pythagoras theorem ,

P² + B² = H²

6² + B² = 7²

B² = 49 - 36

B² = 13

B = \(\sqrt {13 }\)

Now,

secA = \(\frac{H}{B}\)

= \(\frac{7}{√13}\)