From the figure, find out the perpendicular distance of the centre of mass of the system from side AB. ABCD is a square of side 2 m.

0.33 m 1.5 m 1 m  1.33 m

1.33 m

To find the perpendicular distance, we only need to find the y-coordinate. Sum of masses = 4 + 4 + 2 + 2 = 12 kg y-coordinate : (2 x 0 + 4 x 2 + 4 x 2 + 2 x 0)/12 = 1.33 m.