The shortest distance between the line x + y + 2z – 3 = 2x + 3y + 4z – 4 = 0 and the z-axis is :
Answer & explanation
Correct answer: option 2
We have,
$x+y+2 z-3=0, x+2z-2+\frac{3}{2} y=0$
Solving these equations, we get
Y = –2
Thus required shortest distance is 2 units.