If $k+\frac{1}{k}=4$, then what is the value of $k^4+\frac{1}{k^4}$? |
410 192 212 194 |
194 |
If $(x + \frac{1}{x}) = n$ Then, (x2 + x-2) = (n)2 - 2 = b and (x4 + x-4) = b2 - 2 If $k+\frac{1}{k}=4$ Then, (k2 + k-2) = (4)2 - 2 = 14 (k4 + k-4) = 142 - 2 = 194 |