If $k+\frac{1}{k}=4$, then what is the value of $k^4+\frac{1}{k^4}$?
Answer & explanation
Correct answer: option 4
If $(x + \frac{1}{x}) = n$
Then, (x2 + x-2) = (n)2 - 2 = b
and (x4 + x-4) = b2 - 2
If $k+\frac{1}{k}=4$
Then, (k2 + k-2) = (4)2 - 2 = 14
(k4 + k-4) = 142 - 2 = 194